convention in which the [...] operations DWORD 32 dw [...] DINT -2
CODESYS Development System
符用作多路复用器。 OUT := MUX(K, IN0,...,INn) 这意味着: OUT = IN [...] , WORD , DWORD , LWORD
可用循环数据位于数据结构中 in 和 out .您可 [...] 置输入值设置为 in.wActPosition .对于 32 位输入,将值设置为 in
CODESYS Development System
| DWORD | LWORD | SINT [...] | DINT | UDINT | LINT [...] access in an integer
CODESYS Development System
, UINT , DINT , UDINT , BYTE , WORD , DWORD [...] in an error
CODESYS Development System
Bounds : DINT VAR_INPUT index, lower, upper: DINT [...] Bounds : DINT VAR_INPUT index
CODESYS Development System
DWORD; diCount: DINT [...] 常量以及函数调用或表达式的结果 不能 传递给输入变量( VAR_IN [...] points diSize : DINT
> : SINT | INT | DINT [...] | DWORD | LWORD [...] _INPUT iIn: INT; END
在 DWORD 要么 DINT . 空白 [...] 化元素显示在可视化编辑器中插入它的层中。 例子: bIsInForeground 和 VAR bIsIn
VarTypeOfArray : DWORD InOut: Scope [...] VarTypeOfArray DWORD Input type [...] Index0 DINT diIndex1 DINT